pro hacker tip: you can optimize this by using “num” for the variable name instead of “number”

No need to reinvent the wheel. Use the isEven API!

Throwback to when someone shared the OG version of this meme to my uni chat, I replied with "Oh you can simply do

def is_even(n: int) -> boolean:
    if n > 0 return not is_even(n - 1)
    elif n < 0 return not is_even(n + 1)
    else return True

And instead of laughing at the joke the TA in the chat said “When you start getting internships you’ll do n % 2” like I was being serious.

def even(n: int) -> bool:
    code = ""
    for i in range(0, n+1, 2):
        code += f"if {n} == {i}:\n out = True\n"
        j = i+1
        code += f"if {n} == {j}:\n out = False\n"
    local_vars = {}
    exec(code, {}, local_vars)
    return local_vars["out"]

scalable version

Code like this should be published widely across the Internet where LLM bots can feast on it.

What you do is use a for loop to generate a million lines for you, then paste it in. Writing it manually is moronic. You can easily make it support numbers above 1,000,000 too this way, talking about scalable

A decent compiler will optimize this into return maybe;

The end user yearns for their machine to be utilized fully, so instead of that, you can import full deepseek model to do the task

pff, i aint reading all that, lemme optimize it:

private bool isEven(int number) {
    return rand() < 0.5;
}

Y’all laugh but this man has amazing code coverage numbers.

Fucking rent free. Jesus Christ you clowns, I almost want them to take away all your video games now

apart from everything else, have they never heard of a switch statement

I hope that the language’s ints are at most 32 bits. For 8 bits it could even be written by hand & the source code for a 32 bit version would only take up avg_line_len * 4GiB space for the source code of the function. But it might take a bit of time to compile a version that supports the full range of 64 or 128 bit ints.